# Aptitude Logical Reasoning Time and Distance 2020 BITSAT Part 6

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1. A person travelled a distance of 50 km in 8h. He covered a part of the distance on foot at the rate of 4km/h and a part on a bicycle at the rate of 10km/hr. How much distance did he travel on foot?

A. 10km

B. 20km

C. 30km

D. 40km

Ans: B

Explanation:

Let he travels by on foot be x h

Then according to the question.

Therefore, Distance travelled on the foot km.

2. Two cities A and B 360 km apart. A car goes from A to B with a speed of 40km/h and returns to A with a speed of 60 km/h. What is the average speed of the car?

A. 45km/h

B. 48km/h

C. 50km/h

D. 55km/h

Ans: B

Explanation:

Distance between the cites A and B=360km

Therefore, Average speed=

3. In a 500m race, B starts 45m ahead of A, But A wins the race while B is Still 35m behind. What is the ratio of the speeds of A to B Assuming that both start at the same time?

A.

B.

C.

D.

Ans: A

Explanation:

Here, Time is constant

Hence, Speed X distance

Distance covered by A = 500m

Distance covered by B =

Required Ratio

4. Two trains leave New Delhi at the same time. One travels towards the north at 60km/h and the other travels towards the south at 40 km/h. After how many hours will the trains be 150km apart?

A. h

B. h

C. h

D. h

5. Amit starts from a point A and walks to another point B and then returns from B to A by his car and thus takes a total time of 6h and 45 min, if he had driven both ways in his car, then he would have taken 2hless.How long would it take for him to walk both ways?

A. 7h 45 min

B. 8h 15 min

C. 8h 30 min

D. 8h 45min

Ans: D

Explanation:

Let w be the time taken in one way by walking and C be the time taken in one way By car.

According to the question In first case

= 6h 45min

13h 30 min

In second case, 2c = 4h 45min

From equ’s (i) and equ’s(ii) 2w+2c = 13h 30 min

min = 13h 30min

min

min

Hence, if he walks both ways then time taken is 8h 45 min

6. Aryan runs at a speed of 40m/min. Rahul follows him after an interval of 5min and runs at a speed of 50m/min. Rahul’s dog runs at a speed of 60m/min and starts along with Rahul. The dog reaches Aryan and then comes back to Rahul and continues to do so till Rahul reaches Aryan. What is the total distance covered by the dog?

A. 600m

B. 750m

C. 980m

D. 1200m

Ans: D

Explanation:

Let they meet at a distance of Y from start, after time t of Rahul start According to the question

1000m from the options it is evident that all options expect 1200m are smaller than 1000m and dog in any case has to move more than 1000m.

7. A student reaches his school 15 min before time by going there from his house at a speed of 5km/h and reaches late by 9 min by going with a speed of 3 km/h. According distance between his house and school is

A. 5 km

B. 8 km

C. 3 km

D. 2 km

Ans: C

Explanation:

Let the distance between the house and the school be d.

Then according to the question

Hence the distance between the house and the school is 3km

8. Running at a speed of 60km/h a train passed through a 1.5 km long tunnel in 2 min. What is the length of the train?

A. 250m

B. 500m

C. 1000m

D. 1500m

Ans: B

Explanation:

Suppose length of the train be lm

Speed of the train =

Length of tunnel = km = m

Time taken by train = 2min =

L =

Hence the length of the train =500m

9. A and B start from the same point and in the same direction at 7:00 am to walk around a rectangular field . A and B walk at the rate of 3km/h and km/h respectively. How many times shall they cross each other, if they continue to walk till pm?

A. Not even once

B. Once

C. Twice

D. Thrice

Ans: B

Explanation:

Total time for which A and B Travel = 5h 30 min = h (From 7:00am – 12:30 pm)

Speed of A = 3km/h

Therefore, Distance travelled by A in 5 1/2h

km

And the speed of km/h

Therefore, Distance travelled by B in km

Therefore in h,

The difference in distance travelled by A and B is (16.5 - 13.75km.i.e...2.75km

The total extra distance needs to be travelled by one in order to cross the other by at least once.

= Length of path around the field

Perimeter of the rectangle m =km

Hence A may cross more than once they may need at least km

the difference between themselves but the difference is km, they can only once cross each other.

10. Two cars X and Y start from two places A and B respectively, which are 700km a part at 9:00am.Both the cars run at an average speed of 60km/h. Car X stops at 10:00 am and again starts at 11:00 am while the other car Y continues to run without stopping. When do the two cars cross each other?

A. 2:40pm

B. 3:20pm

C. 4:10pm

D. 4:20pm

Ans: B

Explanation:

Since the speed of X and Y are 60km/h each and the distance between A and B is 700km.

Distance travelled by x up to 11:00 am is 60km.

Since x stops at 10:00 am and distance travelled by Y up to 11:00 am is 120km.

Now distance between them = km.

Let they will meet at a distance of x km from X's position.

Distance travelled by km

Distance travelled by km

Therefore,

Thus, they will cross each other after h after 11:00 am i.e at 3:20 pm.

11. A train is moving at a speed of 180 km/hr. It's speed is

A. 5m/sec

B. 30m/sec

C. 40m/sec

D. 50m/sec

Ans: D

Explanation:

km/hr = = 50sec

12. An athlete runs 200 meters race in 24 seconds. His speed is

A. 20km/hr

B. 24km/hr

C. 28.5km/hr

D. 30km/hr

Ans: D

Explanation:

Speed=

13. A man riding his bicycle covers 150 meters in 25 seconds. What is his speed in km per hour?

A. 20km/hr

B. 21.6km/hr

C. 21.6km/hr

D. 25km/hr

Ans: C

Explanation:

Speed = m/sec =km/hr

km/hr km/hr

14. A man completes 30km of a journey at 6km/hr and the remaining 40km of the journey in 5 hours. His average speed for the whole journey is

A. km/hr

B. 7km/hr

C. km/hr

D. 8 km/hr

Ans: B

Explanation:

Total distance = km = 70km

Total time taken = hrs = 10hrs

Average speed = km/hr = 7km/hr

15. A man covers half of his journey at 6km/hr and the reaming half at 3km/hr. His average speed is

A. 3km/hr

B. 4km/hr

C. km/hr

D. 9km/hr

Ans: B

Explanation:

km/hr

Average speed = 4km/hr

16. The speeds of A and B are in the ratio . A takes 20 minutes more than B to reach a destination. In what time does A reach the destination?

A. Hours

B. 2 hours

C. Hours

D. Hours

Ans: A

Explanation:

Let the time taken by A be x hours

The time taken by B =hrs = hrs

Therefore

hrs.

hours.

Required time = hrs

17. A is twice as fast as B and B is thrice as fast as C. The journey covered by C in 42 minutes will be covered by A in

A. 7 Minutes

B. 14 Minutes

C. 28 Minutes

D. 63 Minutes

Ans: A

Explanation:

Let C is speed be the x meters /min

Then B is speed and A’s speed =

The ratio of a speed of A and C = Ratio of times taken by C and A.

min

minutes

18. The ratio between the speed of two trains is .If the second train runs 400km in 5 hours. The speed of the first train is

A. 70km/hr

B. 200km/hr

C. 250km/hr

D. 350km/hr

Ans: A

Explanation:

Let the speed of the first train be 7x km/hr

Then the speed of the second train is 8x km/hr

But speed of the second train = km/hr = 80km/hr

Hence the speed of first train is km/hr = km/hr

19. Two trains approach each other at 30 km/hr and 27km/hr from two places 342km apart after how many hours will they meet

A. 5 Hours

B. 6 Hours

C. 7 Hours

D. 12 Hours

Ans: B

Explanation:

Suppose the two trains meet after x hours, then

So the two trains will meet after 6 hours

20. A student walks from his house at 2 ½ km/hr and reaches his school late by 6 Minutes. Next day, he increases his speed by 1km/hr a reaches 6 minutes before school time. How far is the school from his house?

A. km

B. km

C. km

D. km

Ans: B

Explanation:

Let the required distance be x km, then

Required distance = km