# UGC NET Dec 2013 Paper 1 Solved Part 5 [ CBSE NET-JRF Updates ]

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This is the third part of the UGC Paper 1 Dec 2013 multi-part series where we will discuss the answers for UGC NET exam five questions at a time. The paper this time was tricky. Examrace UGC Paper 1 Series and UGC Online Classes for Paper 1 would equip students to sail through this paper. For more details contact 0999-800-8851 or contactus@examrace.com.

Q. A man pointing to a lady said, "The son of her only brother is the brother of my wife," The lady is related to the man as

(A) Mother's sister

(B) Grand mother

(C) Mother-in-law

(D) Sister of Father-in-law

That man is the brother-in-law of that main who is pointing the lady. And so this relationship explains sister of father-in-law.

Q. In this series 6, 4, 1, 2, 2, 8, 7, 4, 2, 1, 5, 3, 8, 6, 2, 2, 7, 1, 4, 1, 3, 5, 8, 6, 2, 2, 7, 1, 4, 1, 3, 5, 8, 6

How many pairs of successive numbers have a difference of 2 each?

(A) 4

(B) 5

(C) 6

(D) 8

6,4

4,2

5,3

8,6

3,5

8,6

3,5

8,6

So, there are total eight pairs which have a successive difference of 2 each. Difference between two numbers a and b is always positive, i.e., |a-b|=|b-a|. On the other haand, substraction between two numbers would have a sign (+ or -).

Q. The mean marks obtained by a class of 40 students is 65; The mean marks of half of the students is found to be 45. The mean marks of the remaining students is

(A) 85

(B) 60

(C) 70

(D) 65

Total marks of 40 students are 40x65=2600 and total marks of 20 students are 45, i.e., 20x45=900. So the remaining 20 students will have 2600-900 marks which equals to 1700. So, 1700/20=85 marks.

Q. Anil is twice as old as Sunita. Three years ago, he was three times as old as Sunita. The present age of Anil is

(A) 6 years

(B) 8 years

(C) 12 years

(D) 16 years

Let Sunita's age be S, then Anil's age would be A. A=2S and A-3 = 3(S-3). So, A-3=3S-9. So, age of Anil would be 6 years.

Q. Which of the following is a social network?

(A) amazon.com

(B) eBay

(C) gmail.com