# Environmental Science: Numerical Questions – Solar Cell: Calculate Efficiency and Area

Dr. Manishika Jain- Join online Paper 1 intensive course. Includes tests and expected questions.

## Type I – Calculate Efficiency

1. A single solar cell (10 cm×10 cm) produces a voltage of 0.5 V and a current up to 2.5 A. If the solar insolation is 800 W/m^{2},the efficiency of the solar cell is:

⁓15.6 %

⁓24.6 %

⁓12.3 %

⁓10.2 %

Answer: (A) ⁓ 15.6 %

Explanation:

Given Values.

S.I = 800 w/m^{2}

Voltage (V) = 0.5 V

Current (I) = 2.5 A

η =?

Area = 10 cm×10 cm = 10^{-2} m^{2 [}1 cm = 0.01m]

** η =** x 100 …………………………… (i)

Solar Insulation (S.I) **=** ………………………. (ii)

P_{out} = Voltage (V) x Current (I) ……………… (iii)

Using (i), (ii) and (iii) we can deduce.

*η* **=**

*η*

*η* **=**

*η* **=** 0.1562 = 15.62 %

The efficiency of the solar cell is 15.62%.

## Type II – Calculate Area

2. A single solar cell on illumination by insolation of about 800 Wm^{−2} produces a voltage of 0.5 V and a current up to 2.0 A. The efficiency of the solar cell is 12.5%. The area of the cell is:

2×10

^{−2}m^{2}5×10

^{−3}m^{2}4×10

^{−4}m^{2}(4) 10

^{−2}m^{2}

Answer: (D) 10^{-2} m^{2}

Explanation:

Given data’s.

SI = 800 w/m^{2}

Voltage (V) = 0.5 V

Current (I) = 2.0 A

N = 12.5%

Area =?

** η =** x 100 …………………………… (i)

Solar Insulation (S.I) **=** ………………………. (ii)

P_{out} = Voltage (V) x Current (I) ……………… (iii)

Using (i), (ii) and (iii) we can deduce.

*η =*

A =

A = 10^{-2} m^{2}

The Area of the cell is 10^{-2} m^{2} Hence option (D) 10^{-2} m^{2} is the correct answer.

## Type III – Calculate Power

3. Solar insolation on a rectangular module (1.5 m x 2.0 m) of photovoltaic cells is 550 W/m^{2}. If the efficiency of the cells is 12% What is the power output of the module?

396 W

240 W

99 W

198 W

Answer: (D)198 W

Explanation:

Given Values.

S.I = 550 W/m^{2}

η = 12% = 0.12

Area = 1.5 m x 2.0 m = 3 m^{2}

Power = ?

** η =** x 100 …………………………… (i)

Solar Insulation (S.I) **=**

P_{in} = Area * S.I ………………………. (ii)

Using (i) and (ii) we can deduce.

*η* **=**

0.12 =

P = 0.12 * 550 * 3

P = 198 W

The power of the solar cell is 198 W

-Mayank