NSO Level 2 Class 7 Science Paper 2016 − 17 Higher Questions and Answers Part 7

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Question 46:

The given graph shows comparative account of temperature range in four habitats (P, Q, R and S) . Which of the following can be inferred from the given graph?

Graph

(i) Animals inhabiting P may show starling colouration and arboreal adaptations.

(ii) Animals inhabiting Q have thick lips and leathery skin.

(iii) Plants present in S may have thick fleshy photosynthetic stems and leaves modified into spines.

(iv) Animals inhabiting S possess thick layer of subcutaneous fat and have very small body appendages as compared to animals inhabiting Q and R.

(v) Plants like Spruce, Acacia and Opuntia are commonly found in habitat P.

(vi) Animals found in R may show hibernation or seasonal migration.

(A) (i) , (iii) and (vi) only

(B) (ii) , (iv) and (v) only

(C) (i) , (iv) and (v) only

(D) (ii) , (iii) and (vi) only

Question 47:

Refer to the given graph and select the correct option regarding it.

Graph

(A) P carries only oxygenated blood to heart whereas Q carries only deoxygenated blood to heart.

(B) Valves are present in P to prevent backflow of blood.

(C) P always carries blood away from the heart whereas Q always carries blood towards the heart.

(D) P is usually superficially placed whereas Q is usually deep seated.

Question 48:

Refer to the given dichotomous key and identify P, Q, R, S and T.

I. (a) Propagates vegetative by natural methods. – Go to II

(b) Propagates vegetative by artificial methods. – Go to IV

II. (a) New plant develops from stem of parent plant. – Go to III

(b) Roots of parent plant gives rise to new plant. - P

III. (a) Short underground stem covered with fleshy scale leaves. - Q

(b) Modified underground stems (bearing buds) which store food and become swollen. - R

IV. (a) Roots develop from young branch bent towards the ground and covered with soil. - S

(b) It involves placing of stem cutting of one plant over cut stem (having extensive roots) of other plant and tying them. – T

(A) P could be potato whereas R could be garlic.

(B) T could be coriander whereas S could be spinach.

(C) P could be beetroot whereas Q could be turnip.

(D) Q could be onion whereas S could be strawberry.

Question 49:

In a 200 m race, two competitors P and Q reached the finishing line at the same time. Which of the following graphs shows that both the competitors reached the finishing line at time t?

(A)

Two Competitors P and Q-A

(B)

Two Competitors P and Q-B

(C)

Two Competitors P and Q-C

(D)

Two Competitors P and Q-D

Question 50:

Shreya took five solutions labelled as P, Q, R, S and T. She tested them with different indicators and recorded her observations in the given table:

Shreya Took Five Solutions Labelled as P, Q, R, S and T
SolutionMethyl OrangePhenol PhthaleinChina rose
PRedColourlessMagenta
QOrangeColourlessLight Pink
ROrangeColourlessLight Pink
SYellowPinkGreen
TRedColourlessMagenta

Study the given table carefully and fill in the blanks by choosing an appropriate option.

Solution P is (i) , S is (ii) and solution (iii) will show no change in colour with turmeric indicator. Shreya tested (iv) acidic solution (s) in total and solutions (v) can be used for neutralisation reaction.

Study the Given Table Carefully and Fill in the Blanks by Choosing an Appropriate Option
(i)(ii)(iii)(iv)(v)
ASugar SolutionSoap SolutionQ1P and S
BSour MilkAntacidT1R and S
CSoap SolutionSoda waterP2P and S
DVinegarBaking SodaT2S and T

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