# Line slope calculator 2x+8y=68

**Straight line given by points A[2; 8] and B[10; 6]**

## Calculation:

**Slope-intercept form of line:**y = -0.25x+8.5

**Canonical form of the line equation:**2x+8y-68 = 0

**Parametric form of the line equation:**

x = 8t+2

y = -2t+8 ; t ∈ R

**Slope:**m = -0.25

**Slope angle of line: φ =**-14°2'10″ = -0.245 rad

**X intercept:**x

_{0}= 34

**Y intercept:**y

_{0}= q = 8.5

**Distance line from the origin:**d

_{0}= 8.2462

**The length of the segment AB: |AB| =**8.2462

**Vector: AB =**(8; -2)

**Normal vector: n =**(2; 8)

**Midpoint of the segment AB: M =**[6; 7]

**Perpendicular Bisector equation:**8x-2y-34 = 0

**Vector OA = (2; 8) ; |OA| = 8.2462**

**Vector OB = (10; 6) ; |OB| = 11.6619**

**Scalar product OA .OB = 68**

**Angle ∠ AOB = 45° = 0.7854 rad**