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We have `y^(2)=8x" and " x=2` <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NCERT_EXE_MATH_XII_C08_S01_007_S01.png" width="80%"> <br> `:. " Area of shaded region ," A =2int_(0)^(2)sqrt(8x)dx=2.2sqrt2int_(0)^(2)x^(1//2)dx` <br> `=4.sqrt2.[2. (x^(3//2))/3]_(0)^(2)=4sqrt2[2/3 .2sqrt2-0]` <br> `=32/." sq units"`**Area as a definite integral**

**Algorithm for area calculation using horizontal strips**

**Area calculation using horizontal strips for modulus function**

**Impact of sign on area definition change according to sign of function**

**Find the area of the region bounded by the parabola `y^2 = 2x` and the line `x - y = 4`**

**Examples: Find the area of the region bounded by the curve `y^2 = 2y - x` and the y-axis.**

**Area of symmetrical graphs**

**Find the area of the region bounded by the ellipse `x^2 / a^2 + y^2 / b^2 = 1`**

**Integration of sin and cos function in different intervals**

**Examples: f(x) = x for x > 0 and f(x) = x^2 for x < 0; find area with x axis from x = -2 and x = 3.**