# Line slope calculator 6x-10y=-40

**Straight line given by points A[0; 4] and B[10; 10]**

## Calculation:

**Slope-intercept form of line:**y = 0.6x+4

**Canonical form of the line equation:**6x-10y+40 = 0

**Parametric form of the line equation:**

x = 10t

y = 6t+4 ; t ∈ R

**Slope:**m = 0.6

**Slope angle of line: φ =**30°57'50″ = 0.5404 rad

**X intercept:**x

_{0}= -6.6667

**Y intercept:**y

_{0}= q = 4

**Distance line from the origin:**d

_{0}= 3.43

**The length of the segment AB: |AB| =**11.6619

**Vector: AB =**(10; 6)

**Normal vector: n =**(6; -10)

**Midpoint of the segment AB: M =**[5; 7]

**Perpendicular Bisector equation:**10x+6y-92 = 0

**Vector OA = (0; 4) ; |OA| = 4**

**Vector OB = (10; 10) ; |OB| = 14.1421**

**Scalar product OA .OB = 40**

**Angle ∠ AOB = 45° = 0.7854 rad**