# Line slope calculator 5x-4y=-12

**Straight line given by points A[0; 3] and B[4; 8]**

## Calculation:

**Slope-intercept form of line:**y = 1.25x+3

**Canonical form of the line equation:**5x-4y+12 = 0

**Parametric form of the line equation:**

x = 4t

y = 5t+3 ; t ∈ R

**Slope:**m = 1.25

**Slope angle of line: φ =**51°20'25″ = 0.8961 rad

**X intercept:**x

_{0}= -2.4

**Y intercept:**y

_{0}= q = 3

**Distance line from the origin:**d

_{0}= 1.8741

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(4; 5)

**Normal vector: n =**(5; -4)

**Midpoint of the segment AB: M =**[2; 5.5]

**Perpendicular Bisector equation:**4x+5y-35.5 = 0

**Vector OA = (0; 3) ; |OA| = 3**

**Vector OB = (4; 8) ; |OB| = 8.9443**

**Scalar product OA .OB = 24**

**Angle ∠ AOB = 26°33'54″ = 0.4636 rad**