# Find an equation of the tangent line to the curve at the given point. y = sin(sin(x)), (π, 0)?

**Solution:**

**In geometry, the tangent line (or tangent) means a line or plane that intersects a curved line or surface at exactly one point. **

Given:

y = sin(sin(x))

**By chain rule we get,**

y' = cos (sin x) × cos x

When x = π

**y'(π) = cos (sin π) × cos π**

So we get,

y’(π) = cos (0) × (-1)

y’(π) = -1

**We know that the equation of a tangent is**

y - y_{1} = m (x - x_{1})

**Substituting the values**

y - 0 = - 1(x - π)

y = -x + π

y = π - x

**Therefore, the equation of the tangent line is y = π - x.**

## Find an equation of the tangent line to the curve at the given point. y = sin(sin(x)), (π, 0)?

**Summary:**

An equation of the tangent line to the curve at the given point y = sin(sin(x)), (π, 0) is y = π - x.