# Chinese Remainder Theorem (CRT) YouTube Lecture Handout

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Watch Video Lecture on YouTube: Chinese Remainder Theorem (CRT) YouTube Lecture Handout

Chinese Remainder Theorem (CRT) YouTube Lecture Handout

## Recap

• 4 Types of HCF Remainder Problems

• 4 Types of LCM Remainder Problems

• Smallest Number When Divided by x, y and z Leaves Remainder a, b, c?

• x - a = y - b = z - c = common difference d

• Smallest number divided by 2, 3, 4, 5, 6 leaves remainder 1, 2, 3, 4, 5

• Find the smallest number which when divided by 2, 3 and 5 produces 1, 2, 3 as remainders

• Note that 2, 3 and 5 are (pairwise) relatively co-prime

• Find the smallest number which when divided by 7, 9 and 11 produces 1, 2, 3 as remainders

## Simplifying CRT

### Key to Reducing Complicated Calculations- Not Using Full CRT at All!!

• Find the smallest number which when divided by 2, 3 and 5 produces 1, 2, 2 as remainders

• Find the smallest number which when divided by 2, 3 and 5 produces 1, 2, 3 as remainders

• Find the smallest number which when divided by 7, 9 and 11 produces 1, 2, 3 as remainders

## One Small Concept

• Constant Case: Smallest number when divided by x, y and z leaves remainder a, b, c

• x - a = y - b = z - c = common difference d

• LCM (a, b, c) – d

• Convert to Constant Case: Smallest number when divided by x, y and z leaves remainder a, b, c, where

• x - ma = y - mb = z - mc = common difference d

• Use all combining

• 24 produces a remainder 4 when divided by 5

• Find the smallest number which when divided by 7, 9 and 11 produces 1, 2, 3 as remainders

• 7 – 1 = 5 7 – 2 × 1 = 5

• 9 – 2 = 7 9 – 2 × 2 = 5

• 11 – 3 = 8 11 – 2 × 3 = 5

## CRT is Last Resort!!

• Constant Case: Smallest number when divided by x, y and z leaves remainder a, b, c

• x - a = y - b = z - c = common difference d

• LCM (a, b, c) – d

• Convert to Constant Case: Smallest number when divided by x, y and z leaves remainder a, b, c, where

• x - ma = y - mb = z - mc = common difference d

• Use all combining

## Next Class- Word Problems on Chinese Remainder Theorem

6 professors begin courses of lectures on Monday, Tuesday, Wednesday, Thursday, Friday and Saturday, and announce their intentions of lecturing at intervals of 2, 3, 4, 1, 6, 5 days respectively. The regulations of the University forbid Sunday lectures. When first will all six professors simultaneously find themselves compelled to omit a lecture?

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